(9.2) What are Logarithms?
Logarithms in base $a$
$2^3=$
$2^4=$
$3^4=$
$5^2=$
$7^3=$
$2^6=$
$4^0=$
$10^3=$
$10^5=$
$\Rightarrow \quad \log_2 8=$
$\Rightarrow \quad \log_2 16=$
$\Rightarrow \quad \log_3 81=$
$\Rightarrow \quad \log_5 25=$
$\Rightarrow \quad \log_7 343=$
$\Rightarrow \quad \log_2 64=$
$\Rightarrow \quad \log_4 1=$
$\Rightarrow \quad \log 1000=$
$\Rightarrow \quad \log 100000=$
Evaluate.
$\log _{5}125=$
$\log _{3}81=$
$\log _{9}1=$
$\log _{5}25=$
$\log _{4}256=$
$\log _{3}1=$
$\log _{2}16=$
$\log _{3}243=$
$\log _{5}1=$
$\log1000=$
$\log _{5}5=$
$\log _{4}16=$
$\log _{2}32=$
$\log _{6}216=$
$\log _{2}4=$
$\log _{6}6=$
$\log _{6}1=$
$\log _{2}1=$
$\log _{9}81=$
$\log _{5}625=$
$\log _{3}3=$
$\log _{3}27=$
$\log _{8}1=$
$\log _{4}64=$
Evaluate. Give your answers as fractions.
$8^{-1}$
$5^0$
$8^0$
$3^{-2}$
$10^{-1}$
$5^{-2}$
$4^{-2}$
$6^{-3}$
Evaluate.
$\log _{2}\frac{1}{8}=$
$\log _{2}\frac{1}{64}=$
$\log _{4}\frac{1}{4}=$
$\log _{9}\frac{1}{9}=$
$\log _{6}\frac{1}{216}=$
$\log _{6}1=$
$\log _{4}\frac{1}{16}=$
$\log _{2}\frac{1}{16}=$
$\log _{2}\frac{1}{4}=$
$\log\frac{1}{10}=$
$\log _{3}\frac{1}{3}=$
$\log _{2}1=$
$\log _{5}\frac{1}{5}=$
$\log _{9}\frac{1}{729}=$
$\log _{2}\frac{1}{32}=$
Evaluate. Give your answers as fractions.
$256^{\frac{1}{4}}$
$64^{\frac{1}{2}}$
$9^{\frac{1}{2}}$
$64^{-\frac{1}{3}}$
$256^{-\frac{1}{4}}$
$243^{\frac{1}{5}}$
$1000^{\frac{1}{3}}$
$49^{-\frac{1}{2}}$
Evaluate. Give your answers as fractions.
$\log_{64}\frac{1}{8}$
$\log_{512}8$
$\log_{343}\frac{1}{7}$
$\log_{1000}10$
$\log_{16}2$
$\log_{4}2$
$\log_{9}3$
$\log_{729}9$
$\log_{1000}\frac{1}{10}$
$\log_{125}\frac{1}{5}$
$\log_{25}5$
$\log_{243}\frac{1}{3}$
$\log_{9}\frac{1}{3}$
$\log_{49}\frac{1}{7}$
$\log_{8}\frac{1}{2}$