itomath.com

Differential Equations

Extension Problems

Find the solution to the differential equation $\displaystyle \frac{dy}{dx} = \frac{(x+y)^2}{x^2}\;$ for $x\ne 0$ in the form

$\arctan \Bigg($
/
$\Bigg)=\sqrt{3}\ln\bigl($ $\bigl)+C$
The particular solution to the differential equation $\displaystyle \frac{dy}{dx} = \frac{y + x\sqrt{y}}{x}\;$ for $y\ge 0$ when $y\left(1\right)=4$ is
(Hint: make a substitution for $\sqrt{y}$)

$y=\bigl($ $\bigl)^2$
The particular solution to the differential equation $\displaystyle \frac{dy}{dx}=\frac{y}{x+\sqrt{xy}}\;$ for $x>0,y>0$ when $y\left(1\right)=2$ is
(Hint: let $u=\sqrt{\frac{y}{x}}$)

$2\bigl($ $\bigl)-\ln \bigl($ $\bigl)=\sqrt{2}-\ln{2}$
The particular solution to the differential equation $\displaystyle \frac{dy}{dx}=\frac{4x-y+3}{2x+y-3},\;y\left(0\right)=0\;$ is

$\bigl($ $\bigl)^2 \bigl($ $\bigl)^3=$
*the blanks on the left side of the equation are of the form $ax+by+c$ where $a,b$ and $c$ are integers.
*the blank on the right side of the equation is a number.
Consider the differential equation $\;\displaystyle x\frac{dy}{dx}+y=\left(xy\right)^2 \ln x\;$ where $y\left(1\right)=\frac{1}{3}$.
Find the exact value of $y\left(e\right)$.

Consider the differential equation $\;\displaystyle \frac{dy}{dx}+y \ln x=x^{-x}e^{-x}\;$ where $y\left(1\right)=0$.
Find the exact value of $y\left(2\right)$.

Consider the differential equation $\;\displaystyle \frac{dy}{dx}=3x-2y+4$ where $y\left(0\right)=1$
Find $y\left(x\right)$.