Graph the function $f\left(x\right)=0.2\left(x-2\right)^2-3$:
After "$f1\left(x\right)=$" enter $0.2\left(x-2\right)^2-3$ (x is at the bottom)
Graph Trace
To find features of the graph,
press menu > "5 Trace" > "1 Graph Trace"
Move the cursor left and right to find the axes intercepts and the vertex.
The coordinates of the $x$-intercepts are $($
$,0)$ and $($
$,0)$ (to 4 significant figures*)
*If your calculator only displays 3 significant figures, press menu > "9 Settings" > Change "Display Digits" to Float 4
press menu > "5 Trace" > "3 Trace Step..."
Change the trace step to 1. Now move the cursor left and right.
enter 9
This will find the coordinates when $x=9$
press esc to get out of trace mode
Moving the Window
press and hold the center of the trackpad
Now, move your finger along the trackpad. This allows you to grab and move the window. Press again to let go.
move the cursor to one of the axes then press and hold
This allows you to change the scale to zoom in and out. Press again to let go.
This is how you adjust the window manually. Enter the following values:
XMin: -3 / XMax: 7 / XScale: Auto / YMin: -4 / YMax: 5 / YScale: Auto
Using Multiple Functions
Go back to the default window settings ("5 Zoom - Standard")
press tab
After "$f2\left(x\right)=$" enter $-1$ and press enter
To find the intersection of the two functions,
press menu > "6 Analyze Graph" > "4 Intersection". For the lower bound, move the cursor so the dotted line is to the left of one of the intersections and press enter. For the upper bound, move the cursor so the dotted line is to the right of the intersection and press enter
Use "4 Intersection" to find the two solutions to $0.2\left(x-2\right)^2-3=-1\quad x=$
(to 4 significant figures)
Editing, Deleting and Hiding Functions
press tab
press ▴ and ▾ to scroll through your function history
modify $f1\left(x\right)=0.2\left(x-2\right)^2-3$ to $f1\left(x\right)=\left(x-2\right)^2-3$
hide $f2\left(x\right)=-1$ by unchecking the check box
add $f3\left(x\right)=x+8$
Adjust the window and use "4 Intersection" to find the two solutions to $\left(x-2\right)^2-3=x+8\quad x=$