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Zero and Negative Integer Exponents

Evaluate. Give your answers as fractions.

$2^{-2}$

$8^{-2}$

$9^0$

$3^{-3}$

$8^{-3}$

$8^{-1}$

$5^0$

$2^{-3}$

$5^{-3}$

$3^{-2}$

$8^0$

$4^{-2}$

$9^{-1}$

$7^{-1}$

$2^0$

$10^{-1}$

$9^{-2}$

$3^{-4}$

$3^0$

$5^{-2}$

Evaluate.

$\displaystyle\left(\frac{9}{2}\right)^{-1}$
$\displaystyle\left(\frac{8}{7}\right)^{-1}$
$\displaystyle\left(\frac{7}{2}\right)^{-1}$

$\displaystyle\left(\frac{5}{4}\right)^{-2}$
$\displaystyle\left(\frac{3}{2}\right)^{-2}$
$\displaystyle\left(\frac{5}{6}\right)^{-2}$

$\displaystyle\left(\frac{3}{4}\right)^{-2}$
$\displaystyle\left(\frac{9}{8}\right)^{-2}$
$\displaystyle\left(\frac{1}{7}\right)^{-2}$

$\displaystyle\left(\frac{1}{2}\right)^{-3}$
$\displaystyle\left(\frac{8}{5}\right)^{-3}$
$\displaystyle\left(\frac{6}{7}\right)^{-3}$

Evaluate.

$\displaystyle\left(-\frac{6}{7}\right)^{-1}$
$\displaystyle\left(-\frac{3}{4}\right)^{-1}$
$\displaystyle\left(-\frac{2}{7}\right)^{-1}$

$\displaystyle\left(-\frac{7}{9}\right)^{-2}$
$\displaystyle\left(-\frac{2}{7}\right)^{-2}$
$\displaystyle\left(-\frac{9}{8}\right)^{-2}$

$\displaystyle\left(-\frac{3}{5}\right)^{-2}$
$\displaystyle\left(-\frac{4}{9}\right)^{-2}$
$\displaystyle\left(-\frac{5}{8}\right)^{-2}$

$\displaystyle\left(-\frac{3}{8}\right)^{-3}$
$\displaystyle\left(-\frac{1}{9}\right)^{-3}$
$\displaystyle\left(-\frac{8}{9}\right)^{-3}$
Write without negative indices or brackets and simplify.

$\left(2x\right)^{-1}$

$2x^{-1}$

$2^{-1}x$

$\displaystyle\left(\frac{1}{2x}\right)^{-1}$

$\displaystyle\frac{1}{\left(2x\right)^{-1}}$

$\displaystyle\frac{1}{2x^{-1}}$

$\displaystyle\frac{1}{2^{-1}x}$

$\displaystyle\left(\frac{3}{2x}\right)^{-1}$

$\displaystyle\left(\frac{2x}{3}\right)^{-1}$

$\displaystyle\frac{2x^{-1}}{3}$

$\displaystyle\frac{2^{-1}x}{3}$

$\displaystyle\frac{3}{\left(2x\right)^{-1}}$

$\displaystyle\frac{3}{2x^{-1}}$

$\displaystyle\frac{3}{2^{-1}x}$

$\displaystyle\left(\frac{3y}{2x}\right)^{-1}$

$\displaystyle\left(\frac{2x}{3y}\right)^{-1}$

$\displaystyle\frac{2x^{-1}}{3y}$

$\displaystyle\frac{2^{-1}x}{3y}$

$\displaystyle\frac{3y}{\left(2x\right)^{-1}}$

$\displaystyle\frac{3y}{2x^{-1}}$

$\displaystyle\frac{3y}{2^{-1}x}$
Write without negative indices or brackets and simplify.

$\left(2x\right)^{-2}$

$2x^{-2}$

$2^{-2}x$

$\displaystyle\left(\frac{1}{2x}\right)^{-2}$

$\displaystyle\frac{1}{\left(2x\right)^{-2}}$

$\displaystyle\frac{1}{2x^{-2}}$

$\displaystyle\frac{1}{2^{-2}x}$

$\displaystyle\left(\frac{3}{2x}\right)^{-2}$

$\displaystyle\left(\frac{2x}{3}\right)^{-2}$

$\displaystyle\frac{2x^{-2}}{3}$

$\displaystyle\frac{2^{-2}x}{3}$

$\displaystyle\frac{3}{\left(2x\right)^{-2}}$

$\displaystyle\frac{3}{2x^{-2}}$

$\displaystyle\frac{3}{2^{-2}x}$

$\displaystyle\left(\frac{3y}{2x}\right)^{-2}$

$\displaystyle\left(\frac{2x}{3y}\right)^{-2}$

$\displaystyle\frac{2x^{-2}}{3y}$

$\displaystyle\frac{2^{-2}x}{3y}$

$\displaystyle\frac{3y}{\left(2x\right)^{-2}}$

$\displaystyle\frac{3y}{2x^{-2}}$

$\displaystyle\frac{3y}{2^{-2}x}$

$\left(2x^3\right)^{-2}$

$\displaystyle\left(\frac{1}{2x^3}\right)^{-2}$

$\displaystyle\frac{1}{\left(2x^3\right)^{-2}}$

$\displaystyle\left(\frac{3}{2x^3}\right)^{-2}$

$\displaystyle\left(\frac{2x^3}{3}\right)^{-2}$

$\displaystyle\frac{3}{\left(2x^3\right)^{-2}}$

$\displaystyle\left(\frac{3y^4}{2x^3}\right)^{-2}$

$\displaystyle\left(\frac{2x^3}{3y^4}\right)^{-2}$

$\displaystyle\frac{3y}{\left(2x^3\right)^{-2}}$

$\left(2x^{-3}\right)^{-2}$

$\displaystyle\left(\frac{1}{2x^{-3}}\right)^{-2}$

$\displaystyle\frac{1}{\left(2x^{-3}\right)^{-2}}$

$\displaystyle\left(\frac{3}{2x^{-3}}\right)^{-2}$

$\displaystyle\left(\frac{2x^{-3}}{3}\right)^{-2}$

$\displaystyle\frac{3}{\left(2x^{-3}\right)^{-2}}$

$\displaystyle\left(\frac{3y^4}{2x^{-3}}\right)^{-2}$

$\displaystyle\left(\frac{2x^{-3}}{3y^4}\right)^{-2}$

$\displaystyle\frac{3y}{\left(2x^{-3}\right)^{-2}}$