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(3.5) Solving Quadratic Equations

Equations in the form $ax^2+bx+c=0$ where $a\ne 0$ are called quadratic equations.
In this section, we will look at strategies to solve them.

Null Factor Law

Fill in the blanks.

$6\times \square =0$

$\left(-3\right)\times \square =0$

$a\times \square =0$

$\square \times 7=0$

$\square \times \left(-5\right)=0$

$\square \times b=0$

Fill in the blank. If $a\times b=0$, then $a=\square$ or $b=\square$ or both.

Fill in the blanks.

$6\times \left(\square-5\right) =0$

$\left(-3\right) \left(\square +4\right) =0$

$a\times \left(\square -p\right) =0$

$\left(\square +9\right) \times 7=0$

$\left(\square -\frac{1}{2}\right) \left(-5\right)=0$

$\left(\square -q\right) \times b=0$

Solve for $x$. If there are multiple answers, separate them with commas.

$\left(x-2\right)\left(x-1\right)=0\qquad \qquad x=$

$\left(x-7\right)\left(x+7\right)=0\qquad \qquad x=$

$\left(x-4\right)^2=0\qquad \qquad x=$

$x\left(x+8\right)=0\qquad \qquad x=$

$3\left(x-5\right)\left(x+4\right)=0\qquad \qquad x=$

$-2\left(x+6\right)^2=0\qquad \qquad x=$

Solving by Factorizing

Fully factorize. $\qquad x^2-3x+2=$

Solve for $x$.$\qquad x^2-3x+2=0\qquad \qquad x=$

Fully factorize. $\qquad x^2-49=$

Solve for $x$.$\qquad x^2-49=0\qquad \qquad x=$

Fully factorize. $\qquad x^2-8x+16=$

Solve for $x$.$\qquad x^2-8x+16=0\qquad \qquad x=$

Fully factorize. $\qquad x^2+8x=$

Solve for $x$.$\qquad x^2+8x=0\qquad \qquad x=$

Fully factorize. $\qquad 3x^2-3x-60=$

Solve for $x$.$\qquad 3x^2-3x-60=0\qquad \qquad x=$

Fully factorize. $\qquad -2x^2-24x-72=$

Solve for $x$.$\qquad -2x^2-24x-72=0\qquad \qquad x=$

Solve for $x$. If there are multiple answers, separate them with commas.

$x^2-3x=-2\qquad \qquad x=$

$x^2=49\qquad \qquad x=$

$x^2+16=8x\qquad \qquad x=$

$8x=-x^2\qquad \qquad x=$

$3\left(x^2-20\right)=3x\qquad \qquad x=$

$-72=2x\left(x+12\right)\qquad \qquad x=$

Solve for $𝑥$. If there are multiple answers, separate them with commas.

$x^2+4x=0\quad x=$
$x^2+9x=0\quad x=$

Solve for $𝑥$. If there are multiple answers, separate them with commas.

$x^2=-6x\quad x=$
$x^2=-5x\quad x=$

Solve for $𝑥$. If there are multiple answers, separate them with commas.

$3x^2-5x=0\quad x=$
$-2x^2-5x=0\quad x=$

$-5x^2+2x=0\quad x=$
$-3x^2+7x=0\quad x=$

Solve for $𝑥$. If there are multiple answers, separate them with commas.

$7x^2=-3x\quad x=$
$2x^2=-5x\quad x=$

$-2x^2=-7x\quad x=$
$2x^2=7x\quad x=$