(9.2) What are Logarithms?
Logarithms in base $a$
$2^3=$
$2^4=$
$3^4=$
$5^2=$
$7^3=$
$2^6=$
$4^0=$
$10^3=$
$10^5=$
$\Rightarrow \quad \log_2 8=$
$\Rightarrow \quad \log_2 16=$
$\Rightarrow \quad \log_3 81=$
$\Rightarrow \quad \log_5 25=$
$\Rightarrow \quad \log_7 343=$
$\Rightarrow \quad \log_2 64=$
$\Rightarrow \quad \log_4 1=$
$\Rightarrow \quad \log 1000=$
$\Rightarrow \quad \log 100000=$
Evaluate.
$\log _{8}64=$
$\log _{2}32=$
$\log _{7}1=$
$\log _{3}9=$
$\log _{5}1=$
$\log _{9}9=$
$\log _{7}343=$
$\log _{3}81=$
$\log _{3}243=$
$\log _{6}216=$
$\log _{2}8=$
$\log _{2}1=$
$\log _{6}1=$
$\log _{2}4=$
$\log _{2}16=$
$\log1000=$
$\log _{4}64=$
$\log _{8}8=$
$\log _{8}512=$
$\log _{9}729=$
$\log _{6}6=$
$\log _{5}5=$
$\log _{9}81=$
$\log _{3}1=$
Evaluate. Give your answers as fractions.
$3^{-2}$
$10^{-1}$
$2^{-4}$
$3^0$
$4^{-2}$
$9^{-2}$
$7^0$
$2^{-3}$
Evaluate.
$\log _{2}\frac{1}{64}=$
$\log _{2}\frac{1}{2}=$
$\log _{9}\frac{1}{9}=$
$\log _{9}1=$
$\log _{3}\frac{1}{3}=$
$\log _{4}\frac{1}{16}=$
$\log _{8}\frac{1}{512}=$
$\log _{2}\frac{1}{32}=$
$\log _{5}1=$
$\log _{4}\frac{1}{256}=$
$\log _{4}1=$
$\log _{2}\frac{1}{16}=$
$\log _{3}\frac{1}{9}=$
$\log1=$
$\log\frac{1}{1000}=$
Evaluate. Give your answers as fractions.
$729^{-\frac{1}{3}}$
$25^{-\frac{1}{2}}$
$243^{-\frac{1}{5}}$
$49^{-\frac{1}{2}}$
$4^{-\frac{1}{2}}$
$81^{\frac{1}{2}}$
$1000^{-\frac{1}{3}}$
$27^{\frac{1}{3}}$
Evaluate. Give your answers as fractions.
$\log_{9}\frac{1}{3}$
$\log_{16}\frac{1}{4}$
$\log_{49}\frac{1}{7}$
$\log_{64}\frac{1}{4}$
$\log_{64}\frac{1}{2}$
$\log_{8}2$
$\log_{36}6$
$\log_{32}2$
$\log_{16}\frac{1}{2}$
$\log_{1000}10$
$\log_{729}\frac{1}{9}$
$\log_{49}7$
$\log_{64}8$
$\log_{16}2$
$\log_{512}\frac{1}{8}$