(9.2) What are Logarithms?
Logarithms in base $a$
$2^3=$
$2^4=$
$3^4=$
$5^2=$
$7^3=$
$2^6=$
$4^0=$
$10^3=$
$10^5=$
$\Rightarrow \quad \log_2 8=$
$\Rightarrow \quad \log_2 16=$
$\Rightarrow \quad \log_3 81=$
$\Rightarrow \quad \log_5 25=$
$\Rightarrow \quad \log_7 343=$
$\Rightarrow \quad \log_2 64=$
$\Rightarrow \quad \log_4 1=$
$\Rightarrow \quad \log 1000=$
$\Rightarrow \quad \log 100000=$
Evaluate.
$\log _{2}4=$
$\log _{6}1=$
$\log _{2}32=$
$\log _{7}343=$
$\log _{9}729=$
$\log _{6}36=$
$\log _{4}16=$
$\log _{7}1=$
$\log _{2}2=$
$\log _{4}4=$
$\log _{9}9=$
$\log _{5}1=$
$\log _{8}1=$
$\log _{4}64=$
$\log _{3}81=$
$\log _{5}125=$
$\log _{5}25=$
$\log _{5}5=$
$\log _{2}8=$
$\log _{3}1=$
$\log1000=$
$\log _{3}3=$
$\log _{2}64=$
$\log _{3}243=$
Evaluate. Give your answers as fractions.
$8^{-1}$
$7^{-2}$
$7^0$
$4^{-1}$
$3^{-1}$
$2^{-5}$
$4^{-2}$
$5^0$
Evaluate.
$\log _{2}\frac{1}{64}=$
$\log _{2}\frac{1}{16}=$
$\log _{4}\frac{1}{16}=$
$\log _{9}\frac{1}{81}=$
$\log _{3}\frac{1}{81}=$
$\log _{4}\frac{1}{64}=$
$\log _{5}\frac{1}{625}=$
$\log _{4}\frac{1}{256}=$
$\log\frac{1}{100}=$
$\log _{5}\frac{1}{25}=$
$\log _{3}\frac{1}{27}=$
$\log _{2}\frac{1}{32}=$
$\log _{2}\frac{1}{4}=$
$\log _{6}\frac{1}{6}=$
$\log _{7}1=$
Evaluate. Give your answers as fractions.
$125^{-\frac{1}{3}}$
$64^{\frac{1}{2}}$
$8^{-\frac{1}{3}}$
$4^{-\frac{1}{2}}$
$49^{\frac{1}{2}}$
$512^{\frac{1}{3}}$
$32^{\frac{1}{5}}$
$25^{\frac{1}{2}}$
Evaluate. Give your answers as fractions.
$\log_{16}4$
$\log_{216}6$
$\log_{64}\frac{1}{4}$
$\log_{1000}10$
$\log_{243}3$
$\log_{16}2$
$\log_{64}8$
$\log_{8}\frac{1}{2}$
$\log_{100}10$
$\log_{81}9$
$\log_{9}\frac{1}{3}$
$\log_{64}4$
$\log_{216}\frac{1}{6}$
$\log_{729}\frac{1}{9}$
$\log_{36}6$