Rational Equations
Find the Lowest Common Multiple.
$3, 4$
$6, 8$
$9, 15$
$6, 14$
$3, x$
$4, 6x$
$10, 4x$
$9, x^2$
Lowest Common Denominator
$\cancelto{4x}{24x}$
The Lowest Common Multiple of $2x$ and $3$ is
.
To solve $\displaystyle \frac{5}{2x}=\frac{1}{3}$, we can multiply both sides by
.
$\times \displaystyle \frac{5}{2x}=\frac{1}{3} \times$
$\cancelto{3}{6x} \times \displaystyle \frac{5}{\cancelto{1}{2x}}=\frac{1}{\cancelto{1}{3}} \times \cancelto{2x}{6x}$
$=$
$=x$
The Lowest Common Multiple of $6$ and $8x$ is
.
To solve $\displaystyle \frac{5}{6}=\frac{3}{8x}$, we can multiply both sides by
.
$\times \displaystyle \frac{5}{6}=\frac{3}{8x} \times$
$\cancelto{4x}{24x} \times \displaystyle \frac{5}{\cancelto{1}{6}}=\frac{3}{\cancelto{1}{8x}} \times \cancelto{3}{24x}$
$=$
$x=$