Solve for $𝑥$. If there are multiple answers, separate them with commas. Give answers as fractions and not decimals.
The quadratic equation $x^2+2ax-3a=0$ has 2 solutions. One of the solutions is $x=-3$. Find $a$ and the other value of $x$.
If the quadratic equation $x^2-ax+24=0$ has 2 integer solutions, what is the minimum value of $a$? Assume $a$ is positive.
The quadratic equation $x^2+2ax+a^2-4=0$ has 2 solutions. The difference between the two solutions is $4$ and one solution is $5$ times greater than the other solution. Given $a>0$, find the value of $a$ and the two values of $x$ (separate them with a comma).